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Linear Circuits I

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Problem 5 of 5

RL Step Response: Inductor Voltage

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The switch closes at t=0t = 0. Find vLv_L at t=0.02 mst = 0.02\ \text{ms}, in volts.

Vs​18 Vt = 0R1​6 kΩR2​8 kΩL0.2 H+−vL​iL​
V

Answers within 2% are accepted. Units with SI prefixes work too, like 0.003 A or 3 mA. Use a minus sign for negative values.

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